Optimal. Leaf size=159 \[ -\frac{a^3 \cos ^9(c+d x)}{9 d}+\frac{5 a^3 \cos ^7(c+d x)}{7 d}-\frac{4 a^3 \cos ^5(c+d x)}{5 d}-\frac{3 a^3 \sin ^3(c+d x) \cos ^5(c+d x)}{8 d}-\frac{17 a^3 \sin (c+d x) \cos ^5(c+d x)}{48 d}+\frac{17 a^3 \sin (c+d x) \cos ^3(c+d x)}{192 d}+\frac{17 a^3 \sin (c+d x) \cos (c+d x)}{128 d}+\frac{17 a^3 x}{128} \]
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Rubi [A] time = 0.323036, antiderivative size = 159, normalized size of antiderivative = 1., number of steps used = 17, number of rules used = 7, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.241, Rules used = {2873, 2568, 2635, 8, 2565, 14, 270} \[ -\frac{a^3 \cos ^9(c+d x)}{9 d}+\frac{5 a^3 \cos ^7(c+d x)}{7 d}-\frac{4 a^3 \cos ^5(c+d x)}{5 d}-\frac{3 a^3 \sin ^3(c+d x) \cos ^5(c+d x)}{8 d}-\frac{17 a^3 \sin (c+d x) \cos ^5(c+d x)}{48 d}+\frac{17 a^3 \sin (c+d x) \cos ^3(c+d x)}{192 d}+\frac{17 a^3 \sin (c+d x) \cos (c+d x)}{128 d}+\frac{17 a^3 x}{128} \]
Antiderivative was successfully verified.
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Rule 2873
Rule 2568
Rule 2635
Rule 8
Rule 2565
Rule 14
Rule 270
Rubi steps
\begin{align*} \int \cos ^4(c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^3 \, dx &=\int \left (a^3 \cos ^4(c+d x) \sin ^2(c+d x)+3 a^3 \cos ^4(c+d x) \sin ^3(c+d x)+3 a^3 \cos ^4(c+d x) \sin ^4(c+d x)+a^3 \cos ^4(c+d x) \sin ^5(c+d x)\right ) \, dx\\ &=a^3 \int \cos ^4(c+d x) \sin ^2(c+d x) \, dx+a^3 \int \cos ^4(c+d x) \sin ^5(c+d x) \, dx+\left (3 a^3\right ) \int \cos ^4(c+d x) \sin ^3(c+d x) \, dx+\left (3 a^3\right ) \int \cos ^4(c+d x) \sin ^4(c+d x) \, dx\\ &=-\frac{a^3 \cos ^5(c+d x) \sin (c+d x)}{6 d}-\frac{3 a^3 \cos ^5(c+d x) \sin ^3(c+d x)}{8 d}+\frac{1}{6} a^3 \int \cos ^4(c+d x) \, dx+\frac{1}{8} \left (9 a^3\right ) \int \cos ^4(c+d x) \sin ^2(c+d x) \, dx-\frac{a^3 \operatorname{Subst}\left (\int x^4 \left (1-x^2\right )^2 \, dx,x,\cos (c+d x)\right )}{d}-\frac{\left (3 a^3\right ) \operatorname{Subst}\left (\int x^4 \left (1-x^2\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=\frac{a^3 \cos ^3(c+d x) \sin (c+d x)}{24 d}-\frac{17 a^3 \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{3 a^3 \cos ^5(c+d x) \sin ^3(c+d x)}{8 d}+\frac{1}{8} a^3 \int \cos ^2(c+d x) \, dx+\frac{1}{16} \left (3 a^3\right ) \int \cos ^4(c+d x) \, dx-\frac{a^3 \operatorname{Subst}\left (\int \left (x^4-2 x^6+x^8\right ) \, dx,x,\cos (c+d x)\right )}{d}-\frac{\left (3 a^3\right ) \operatorname{Subst}\left (\int \left (x^4-x^6\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{4 a^3 \cos ^5(c+d x)}{5 d}+\frac{5 a^3 \cos ^7(c+d x)}{7 d}-\frac{a^3 \cos ^9(c+d x)}{9 d}+\frac{a^3 \cos (c+d x) \sin (c+d x)}{16 d}+\frac{17 a^3 \cos ^3(c+d x) \sin (c+d x)}{192 d}-\frac{17 a^3 \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{3 a^3 \cos ^5(c+d x) \sin ^3(c+d x)}{8 d}+\frac{1}{16} a^3 \int 1 \, dx+\frac{1}{64} \left (9 a^3\right ) \int \cos ^2(c+d x) \, dx\\ &=\frac{a^3 x}{16}-\frac{4 a^3 \cos ^5(c+d x)}{5 d}+\frac{5 a^3 \cos ^7(c+d x)}{7 d}-\frac{a^3 \cos ^9(c+d x)}{9 d}+\frac{17 a^3 \cos (c+d x) \sin (c+d x)}{128 d}+\frac{17 a^3 \cos ^3(c+d x) \sin (c+d x)}{192 d}-\frac{17 a^3 \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{3 a^3 \cos ^5(c+d x) \sin ^3(c+d x)}{8 d}+\frac{1}{128} \left (9 a^3\right ) \int 1 \, dx\\ &=\frac{17 a^3 x}{128}-\frac{4 a^3 \cos ^5(c+d x)}{5 d}+\frac{5 a^3 \cos ^7(c+d x)}{7 d}-\frac{a^3 \cos ^9(c+d x)}{9 d}+\frac{17 a^3 \cos (c+d x) \sin (c+d x)}{128 d}+\frac{17 a^3 \cos ^3(c+d x) \sin (c+d x)}{192 d}-\frac{17 a^3 \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{3 a^3 \cos ^5(c+d x) \sin ^3(c+d x)}{8 d}\\ \end{align*}
Mathematica [A] time = 0.815539, size = 106, normalized size = 0.67 \[ \frac{a^3 (5040 \sin (2 (c+d x))-12600 \sin (4 (c+d x))-1680 \sin (6 (c+d x))+945 \sin (8 (c+d x))-52920 \cos (c+d x)-16800 \cos (3 (c+d x))+4032 \cos (5 (c+d x))+2340 \cos (7 (c+d x))-140 \cos (9 (c+d x))+30240 c+42840 d x)}{322560 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.04, size = 216, normalized size = 1.4 \begin{align*}{\frac{1}{d} \left ({a}^{3} \left ( -{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4} \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{9}}-{\frac{4\, \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{63}}-{\frac{8\, \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{315}} \right ) +3\,{a}^{3} \left ( -1/8\, \left ( \sin \left ( dx+c \right ) \right ) ^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{5}-1/16\,\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{ \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+3/2\,\cos \left ( dx+c \right ) \right ) \sin \left ( dx+c \right ) }{64}}+{\frac{3\,dx}{128}}+{\frac{3\,c}{128}} \right ) +3\,{a}^{3} \left ( -1/7\, \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{5}-{\frac{2\, \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{35}} \right ) +{a}^{3} \left ( -{\frac{\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{6}}+{\frac{\sin \left ( dx+c \right ) }{24} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{dx}{16}}+{\frac{c}{16}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.06261, size = 186, normalized size = 1.17 \begin{align*} -\frac{1024 \,{\left (35 \, \cos \left (d x + c\right )^{9} - 90 \, \cos \left (d x + c\right )^{7} + 63 \, \cos \left (d x + c\right )^{5}\right )} a^{3} - 27648 \,{\left (5 \, \cos \left (d x + c\right )^{7} - 7 \, \cos \left (d x + c\right )^{5}\right )} a^{3} - 1680 \,{\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} + 12 \, d x + 12 \, c - 3 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{3} - 945 \,{\left (24 \, d x + 24 \, c + \sin \left (8 \, d x + 8 \, c\right ) - 8 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{3}}{322560 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.56711, size = 300, normalized size = 1.89 \begin{align*} -\frac{4480 \, a^{3} \cos \left (d x + c\right )^{9} - 28800 \, a^{3} \cos \left (d x + c\right )^{7} + 32256 \, a^{3} \cos \left (d x + c\right )^{5} - 5355 \, a^{3} d x - 105 \,{\left (144 \, a^{3} \cos \left (d x + c\right )^{7} - 280 \, a^{3} \cos \left (d x + c\right )^{5} + 34 \, a^{3} \cos \left (d x + c\right )^{3} + 51 \, a^{3} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{40320 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 22.4269, size = 486, normalized size = 3.06 \begin{align*} \begin{cases} \frac{9 a^{3} x \sin ^{8}{\left (c + d x \right )}}{128} + \frac{9 a^{3} x \sin ^{6}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{32} + \frac{a^{3} x \sin ^{6}{\left (c + d x \right )}}{16} + \frac{27 a^{3} x \sin ^{4}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{64} + \frac{3 a^{3} x \sin ^{4}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{16} + \frac{9 a^{3} x \sin ^{2}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{32} + \frac{3 a^{3} x \sin ^{2}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{16} + \frac{9 a^{3} x \cos ^{8}{\left (c + d x \right )}}{128} + \frac{a^{3} x \cos ^{6}{\left (c + d x \right )}}{16} + \frac{9 a^{3} \sin ^{7}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{128 d} + \frac{33 a^{3} \sin ^{5}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{128 d} + \frac{a^{3} \sin ^{5}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{16 d} - \frac{a^{3} \sin ^{4}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{5 d} - \frac{33 a^{3} \sin ^{3}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{128 d} + \frac{a^{3} \sin ^{3}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{6 d} - \frac{4 a^{3} \sin ^{2}{\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{35 d} - \frac{3 a^{3} \sin ^{2}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{5 d} - \frac{9 a^{3} \sin{\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{128 d} - \frac{a^{3} \sin{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{16 d} - \frac{8 a^{3} \cos ^{9}{\left (c + d x \right )}}{315 d} - \frac{6 a^{3} \cos ^{7}{\left (c + d x \right )}}{35 d} & \text{for}\: d \neq 0 \\x \left (a \sin{\left (c \right )} + a\right )^{3} \sin ^{2}{\left (c \right )} \cos ^{4}{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.44074, size = 212, normalized size = 1.33 \begin{align*} \frac{17}{128} \, a^{3} x - \frac{a^{3} \cos \left (9 \, d x + 9 \, c\right )}{2304 \, d} + \frac{13 \, a^{3} \cos \left (7 \, d x + 7 \, c\right )}{1792 \, d} + \frac{a^{3} \cos \left (5 \, d x + 5 \, c\right )}{80 \, d} - \frac{5 \, a^{3} \cos \left (3 \, d x + 3 \, c\right )}{96 \, d} - \frac{21 \, a^{3} \cos \left (d x + c\right )}{128 \, d} + \frac{3 \, a^{3} \sin \left (8 \, d x + 8 \, c\right )}{1024 \, d} - \frac{a^{3} \sin \left (6 \, d x + 6 \, c\right )}{192 \, d} - \frac{5 \, a^{3} \sin \left (4 \, d x + 4 \, c\right )}{128 \, d} + \frac{a^{3} \sin \left (2 \, d x + 2 \, c\right )}{64 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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